what is the angular momentum of a 0.310 kg ball rotating on the end of a thin string in a circle of radius 1.45 m at an angular speed of 10.6 rad/s ?

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08-11-2022
Physics

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what is the angular momentum of a 0.310 kg ball rotating on the end of a thin string in a circle of radius 1.45 m at an angular speed of 10.6 rad/s ?

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-11-20T12:52:47-05:00

4.76 kg [tex]m^{2} / sec[/tex] will be the angular momentum of a 0.310 kg ball rotating on the end of a thin string in a circle of radius 1.45 m at an angular speed of 10.6 rad/s

L = m*v*r

m = mass

v = velocity

r = radius

L (angular momentum ) = m*v*r

= 0.310 * 1.45 * 10.6

= 4.76 kg [tex]m^{2} / sec[/tex]

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