. a diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. calculate the magnification.



Answer :

A diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. The magnification will be  -12.833 cm

diverging lens = concave lens

focal length = - 33 cm

u = - 21 cm

magnification = image distance / object distance

using lens formula

1/v - 1/u = 1/f

1/v = 1/f + 1/u

    = 1/-33 -1/21

v   = -12.833 cm

A diverging lens has a focal length that has a magnitude of 33.0 cm. an object is placed 21.0 cm in front of this lens. The magnification will be  -12.833 cm

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