The period of oscillation, if at a given time the magnitude of acceleration of a mass is 9 m/s² when its position is 4 meters from equilibrium is 4.188 s
Acceleration can be expressed as,
a ( t ) = - ω² x ( t )
ω² = a ( t ) / - x ( t )
ω² = 9 / - ( - 4 )
ω² = 9 / 4
ω = 3 / 2
ω = 1.5 rad / s
T = 2 π / ω
T = Time period
ω = Angular velocity
T = 2 * 3.14 / 1.5
T = 4.188 s
Therefore, the period of oscillation is 4.188 s
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