a 4.0 m radius circular platform accelerates from rest at 10.0 rad/s2. what is the linear displacement of the edge of the circular platform after 2.0 s?

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08-11-2022
Physics

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a 4.0 m radius circular platform accelerates from rest at 10.0 rad/s2. what is the linear displacement of the edge of the circular platform after 2.0 s?

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smecloudbird18 smecloudbird18 · Answer 1 · 2022-11-20T19:02:36-05:00

A 4.0 m radius circular platform accelerates from rest at 10.0 rad/s2. The linear displacement of the edge of the circular platform after 2.0 s will be 80 m .

theta = omega * t + 1/2 * alpha * [tex]t^{2}[/tex]

omega = angular velocity

alpha = angular acceleration

using equation

theta = omega * t + 1/2 * alpha * [tex]t^{2}[/tex]

= 0 + 1/2 * 10 * 4 = 20 rad

linear displacement = radius * theta

= 4 * 20 = 80 m

A 4.0 m radius circular platform accelerates from rest at 10.0 rad/s2. The linear displacement of the edge of the circular platform after 2.0 s will be 80 m .

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