a lamina occupies the part of the disk in the first quadrant and the density at each point is given by the function . a. what is the total mass? b. what is the moment about the x-axis, ? c. what is the moment about the y-axis, ? d. where is the center of mass? ( , ) e. what is the moment of inertia about the origin, ?



Answer :

The center of mass of the lamina would be in the middle of the axis and the mass of the lamina is 25.

For this, we will use the polar coordinates. According to the change of coordinates, where r and theta are the new parameters. Given a point (x,y) in the plane, r is the distance from (x,y) to the origin and theta is the angle formed between the line that joins the origin and the point, and the x-axis.

        We need to describe the region D in terms of the new parameters. Replacing the values of x,y in the given inequality, we get that . Since and r>0 we get that r<=5. On the other side, in order to describe the whole region of the first quadrant, we need to sweep the angle theta from 0 to. With that, we can calculate the mass of the lamina as follows here, the extra r appears as the Jacobian coordinates.

Learn more about lamina and refer to numerical at,

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