after a capacitor is charged, it is removed from the power source. the separation between the plates is 4.0 mm and the electric field at a midpoint between the plates is 200 v/m. when the plates are pushed to a separation of 2.0 mm, the electric field at midpoint between the plates is:

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08-11-2022
Physics

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after a capacitor is charged, it is removed from the power source. the separation between the plates is 4.0 mm and the electric field at a midpoint between the plates is 200 v/m. when the plates are pushed to a separation of 2.0 mm, the electric field at midpoint between the plates is:

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Qwmarket Qwmarket · Answer 1 · 2022-11-14T09:47:35-05:00

The electric field at midpoint between the plates will be 200 v/m.

Since the capacitor is charged, it has an electric field between its plates. When the capacitor is removed from the power source, there is no longer a force pushing electrons onto one plate and off of the other, so there are still equal numbers of positive and negative charges on each plate. This means that the electric field remains unchanged from when it was fully charged.

When you push the plates together to 2 mm apart, this causes more surface area to be covered by electrons. This means that more electrons will be pushed onto one plate than off of it until they are evenly distributed across both plates again.

This means there will be more negative charge on one plate than positive charge on the other—the same way it was before you pushed them together—and therefore an increased electric field between them at midpoint between their surfaces.

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