Answer :
The position on the meter stick is 25 cm.
Solution:
The center of mass of the meter stick will be at 0.5 m and its torque about the pivot point will be T1 = mg(0.5 - 0.3)
T1 = 0.5*9.81*0.2 = 0.981 N-m (clockwise)
So we have to add 2 kg mass on the left side of the pivot so that it has a counter-clockwise torque about the pivot point.
Let us position it at x the its torque about pivot point will be T2 = mg(0.3 - x) = 2*9.81*(0.3 - x)
To support the stick T1 = T2
0.981 = 2*9.81*(0.3 - x)
0.3 - x = 0.05
x = 0.25 m = 25 cm.
The position of the center of gravity is the average position of the total weight of the object. The center of mass is the object's balance point, also represented as the point where all its mass appears to reside. Sticks are measured in two ways. Measure straight from the top of the shaft to the blade or from the top of the shaft to the heel with the shaft up against a wall. Remember If you measure your street shoe stick it will feel about 3-4 inches shorter on the ice.
Learn more about The meter stick here:-https://brainly.com/question/27754891
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