an 0.45-kg object is being pulled with a tension force of 14.2 n at a constant velocity of 3.41 m/s. what is the force of friction acting on the object?

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08-11-2022
Physics

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an 0.45-kg object is being pulled with a tension force of 14.2 n at a constant velocity of 3.41 m/s. what is the force of friction acting on the object?

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kjuli1766 kjuli1766 · Answer 1 · 2022-11-15T03:59:42-05:00

The forces of friction acting on the object are 12.67 N.

Friction is the force resisting the relative motion of sturdy surfaces, fluid layers, and material factors sliding towards each specific. There are numerous styles of friction. Dry friction is a strain that opposes the relative lateral movement of two stable surfaces in touch.

Calculation:-

ma - 14.2 N = Friction force

14.2 N - 0.45 × 3.41 = 12.67 N

Friction is the shape of contact pressure. It exists between the surfaces that are in touch. The frictional force relies upon the character of the floor in contact. The rougher the ground, the extra friction is involved. The frictional force is proportional to the urgent pressure, which is the burden of the body. it's miles impartial of the place of the touch.

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