a rigid rod of length and mass has small point like masses and attached as shown. here 0.08 kg, 0.6 m. the rod is spinning in a horizontal plane about a vertical axis passing through the smaller mass . the linear speed of mass is 2.5 m/s. find the angular momentum of the rod and masses system with respect to the point on the fixed axis that intersects with the rod.



Answer :

The angular momentum of the rod and masses system is  2.5 ms.

Angular momentum is the rotational analog of linear momentum. it is an essential bodily quantity due to the fact it is a conserved amount—the entire angular momentum of a closed device remains constant. Angular momentum has both a route and a value, and both are conserved.

Angular momentum is defined as The property of any rotating item given via second of inertia instances angular velocity. it's far the property of a rotating frame given with the aid of the made of the instant of inertia and the angular pace of the rotating item.

Calculation:-

The moment of inertia of the system about the basics is,

I e mos + (2m) [2 = me+ 2m22 3

= 7(0-0819) 0.6m) 2

= 0.0672 LG. ma ✓

= 2.5 ms

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