Answer :
The crate needs to put in 1000.63 Joule of work in order to shift its velocity from 0 to 6.67 m/s in the direction of 63.00 south-east.
What work is being done?
We are aware that the definition of labor is the multiplication of the force operating in the direction of the displacement (d) and its component.
Given,
A 22 kg container is initially traveling 440 degrees west of north at a speed of 3.90 m/s.
the cosine formula was used to compute the outcome velocity.
where angle ∅ = 440 + 90 + 63 = 593°
v² = (3.90)²+(6.67)² - 2(3.9)(6.67) cos 593
v² = 59.6989 + 52.026 × 0.601
v² = 59.6989 + 31.2676
v² = 90.9665
Resultant velocity V = 9.5376
V = 9.53 m/s
To calculate the much work that must be done on the crate to change its velocity to 6.67 m/s in a direction 63.0° south of east, Because energy and labor are equivalent, the kinetic energy formula is used.
W = 1/2mv²
Where,
m = 22 kg and
v = resultant velocity = 9.53 m/s
W = 0.5 x 22 x (9.53)²
W = 1000.63 Joule
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