Answer :
Am mass of 0.431 kg should be added to the suspended mass so that the period changes from 1.25s to 1.75s.
The time period of the mass oscillating is given by,
T = 2π√(M/k)
Where,
M is the mass suspended by the spring and K is the spring constant,
The mass suspended is 0.145 kg and the time period is 1.25 seconds.
So, putting values,
1.25 = 2π√(0.415/K) ......Equation 2,
Let us say, that we have to add a mass M to the object so that the period changes to 1.75 seconds.
So, we can write,
1.75 = 2π√(0.415+M/K) ......Equation 1
Dividing the equations 1 and 2, we get,
M = 0.431 kg.
So, a mass of 0.431 kg should be added to change the time period.
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