Answer :
The Deceleration required by the to avoid the pileup is 4.71m/s².
The car is travelling with a speed of 82 km/h. The driver starts to apply breaks at a distance of 55 m.
The minimum deceleration required to make the car stop to avoid a pileup is given by,
a = u²/2s
u is the initial velocity,
a is the negative acceleration,
s is the displacement of the car,
The speed is 82 km/h, converting it, the speed is 22.77m/s.
Putting values,
a = 22.77 x 22.77/2 x 55
a = 4.71m/s².
The negative acceleration or the deceleration required is 4.71m/s².
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