Answer :
Using the concepts of work, power and energy, we got that 90hp is the average power delivered by the engine for a 1500-kg car accelerates from 0 to 25 m/s in 7.0 s with negligible friction and the air resistance.
we know that,
Work = force x distance
= (ma)x(d)
Similarly, power = energy/time
Initial velocity(V[tex]_i[/tex])=0m/sec
and Final velocity(V[tex]_f[/tex]) = 25 m/s
and t = 7 sec.
We know that acceleration is defined change of velocity in per unit time
Therefore, acceleration =(25-0)/7=3.6m/sec²
and distance(d) = 87.5 meters
Now, we have mass and acceleration, so on putting the values we get
=>F = ma
=>F=1500×3.6
=>F=5400Newton,
Therefore, energy will be equal to=Force × distance
=>Energy=5400×87.5
Energy = 5400×87.5 = 4.7×[tex]10^{5}[/tex] Joules
Therefore, power will be equal to Energy/Time
=>Power= 4.7×[tex]10^{5}[/tex]/7sec
=>Power= 67,500 Watts or 90 hp.
Hence, if a 1500-kg car accelerates from 0 to 25 m/s in 7.0 s with negligible friction and air resistance, the average power delivered by the engine is 90hp.
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