an object of mass 2.9 kg is attached to a spring that has a spring constant of 69 n/m. suppose the spring is stretched a maximum distance of 0.136 m before the object starts to move. what is mu s, the coefficient of static friction?



Answer :

The static friction value is the value from zero to the minimum force required to initiate motion. The formula for calculating static friction is:

Static Friction = Normal Force x Static Friction Coefficient.

The maximum or limit of friction between two surfaces is FMAX=μR F MAX = μR. where μ is the coefficient of friction and R is the normal reaction between two surfaces. The coefficient of friction is a measure of surface roughness, with rougher surfaces having higher values. Therefore, as the car makes a circular motion, the necessary centripetal force is provided by the frictional force. Therefore, the coefficient of static friction between a car tire and the road surface is 0.53.

Learn more about friction here-

https://brainly.com/question/13000653

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