an 82-kg stunt man falls off the top of a large building. after falling for 65 meters he has a speed of 22 m/s. assuming he was initially at rest, what was the average force of air resistance exerted on the stunt man during his fall?



Answer :

The average drag force on the stuntman during a fall is 305.29 N. force is a push or a pull.

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Start by collecting the kinetic energy of the stuntman.

Mass (m) = 82 kg

Velocity (v) = 22 m/s

Kinetic Energy (KE) =?

KE = 19844 J

Finally, determine the average drag applied to the stunt. This is obtained as follows:

Distance = 65 meters

Energy = 19844 J

Average force =?

Energy = Work

Work (W) = Force (F) × Displacement (d)

W = Fd

So

E = W = Fd

19844 = F × 65

Divide both sides 65

F = 19844 / 65

F = 305.29 N

So, from the above calculation we can conclude that the average force is 305.29 N

Learn more about energy here-

https://brainly.com/question/1932868

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