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08-11-2022
Physics

Answered

what is the rotational inertia of a solid iron disk of mass 41.0 kg with a thickness of 5.00 cm and radius of 30.0 cm, about an axis perpendicular to the disk and passing through its center?

Answer :

08-11-2022

Answer:

I = 1/2 M R^2 moment of inertia of solid disk

I = 1/2 * 41.0 kg * (.3 m)^2

I = 20.5 kg * .09 m^2 = 1.85 kg-m^2

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