The electric field should be applied is 3,694.5 .
As we know from electromagnetic theory we have a relation with electric field and magnetic field with force, which is
F = qE + qv x B
or we can write that
F = qE + qvBsinФ
To allow proton to move with the constant speed, we need to apply zero external force
It means F = 0
or we can write that
qE = -qvBsinФ
putting the appropriate values, we get
E = 4105 x 0.9
E = 3,694.5
Hence the magnitude of the electric field is 3,694.5 .
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