Answer :
A rock is tossed straight up from a height of 1.20 m above the ground with an initial speed of 7.54 m/s. It will take 0.15 seconds to hit the rock ground
height = displacement = 1.20 m
initial speed = u = 7.54 m/s
final speed = v = 0
time = ?
Using kinematic equation
s = u*t + 1/2 * g * [tex]t^{2}[/tex]
1.20 = 7.54 t + 1/2 * 9.8 * [tex]t^{2}[/tex]
= 4.9 [tex]t^{2}[/tex] + 7.54 t - 1.20
t = 0.15 seconds
It will take 0.15 seconds to hit the rock ground
To learn more about kinematic equation here :
https://brainly.com/question/12351668
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