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a 65-kg boy and a 45-kg girl use an elastic rope while engaged in a tug-of-war on an icy, fricktionless surface. if the acceleration fo the girl toward the boy is 3.0 m/s^2, find the magnitude of the acceleration of the boy toward the girl.



Answer :

The magnitude of the acceleration of the boy toward the girl was 0.82 m/s².

Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.

Calculation:-

mass of girl = 45 kg

acceleration of girl = 3 m/s²

F = ma

   = 45 × 3

  = 135 N

According to newton's third law equal but the opposite force is applied to the boy towards the girl.

135 = 65 × a

a = 135/165

  = 0.82 m/s²

Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. Movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.

Learn more about acceleration here:- https://brainly.com/question/29110429

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