Answered

a car enters the freeway with a speed of 5.9 m/s and accelerates uniformly for 3.3 km in 2.9 min. how fast is the car moving after this time?



Answer :

The car will move fast with the velocity of 32.03 m/s

What is acceleration?

  • Acceleration: the rate at which the speed and direction of a moving object vary over time.
  • A point or object going straight ahead is accelerated when it accelerates or decelerates.
  • Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.
  • Both effects contribute to the acceleration for all other motions.
  • Acceleration is a vector quantity, since it has both a magnitude and a direction. A vector quantity is also velocity.
  • The velocity vector change during a time interval divided by the time interval is the definition of acceleration.
  • The limit of the ratio of the change in velocity during a given time interval to the time interval as the time interval approaches zero determines the instantaneous acceleration (at a specific time and location)
  • For instance, acceleration will be stated in meters per second per second if velocity is expressed in meters per second.

Calculation

Initial velocity(u) = 5.9 m/s

Distance traveled = 3.3 km = 3300 m

Time = 2.9 min = 2.9×60 = 174 seconds

Formula,

[tex]s=\frac{1}{2} (u+v)t[/tex]

[tex]3300=\frac{1}{2} (5.9+v)*174[/tex]

[tex]v= (\frac{6600}{174} -5.9)m/s[/tex]

v = 37.93–5.9 = 32.03 m/s

Hence, the car will move fast with velocity = 32.03 m/s

To learn more about acceleration, refer to

https://brainly.com/question/460763

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