one year, the scores on the test were approximately normally distributed with a mean of 420 and a standard deviation of 70. the 81st percentile for this test was . . .

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08-11-2022
Mathematics

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one year, the scores on the test were approximately normally distributed with a mean of 420 and a standard deviation of 70. the 81st percentile for this test was . . .

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ShubhamSrivastava ShubhamSrivastava · Answer 1 · 2022-11-11T22:38:10-05:00

81 percentile of the given test is 482

The square root of the means of the squared deviations from the arithmetic mean is known as the standard deviation. Standard deviation is used in finance to quantify the risks associated with an investment instrument.

Given that the Marble Academy of Whoville conducts an annual test for all high school juniors one year, the scores on the test were approximately normally distributed with a mean of 420 and a standard deviation of 70

Here mean μ = 420 and Standard deviation σ = 70

We have find 81 percentile of this test = ?

The z score corresponding to the area 0.81 is

Z = 0.88 By standard normal table

X = μ + z σ

X = 420 + 0.88 x 70

= 420 + 62

= 482

Therefore 81 percentile of this test is 482

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