a horizontal force is applied to a glider moving along a horizontal air track bringing it to a stop in t seconds. if the same force is applied to a second glider with half the mass and four times the initial velocity, how long does it take for the glider to come to a stop?



Answer :

ayune

The second glider will stop after it travels the distance of 8 times the distance of the first glider.

Let subscript 1 and 2 represent parameters related to glider 1 and glider 2.

According to the Newton's law:

F = m . a

Where:

F = force

m = mass

a = acceleration

Since both gliders received the same forces,

F₁ = F₂

m₁ . a₁ = m₂ . a₂

m₁ . a₁ = 1/2m₁ . a₂

a₂ = 2a₁

Hence, the acceleration of the 2nd glider is twice of that of the 1st glider.

Velocity formula for decelerated move

v² = u² - 2.a.s

Where:

v = final velocity

u = initial velocity

s = distance.

Since the gliders stop, v = 0

Hence,

u₁² = 2.a₁.s₁

u₂² = 2.a₂ . s₂

Substitute u₂ = 4u₁,  a₂ = 2a₁

(4u₁)² = 2.(2a₁) . s₂

16 u₁² = 4 a₁ . s₂

16. (2.a₁.s₁) = 4 a₁ . s₂

s₂ = 8 s₁

Hence, the distance of glider 2 is 8 times the distance of glider 1

Learn more about velocity here:

https://brainly.com/question/26170046

#SPJ4

Other Questions