Answer :
When binomial distribution is used, the probability that at least 275 rooms are occupied is 0.96
Option b. is correct
We have the following parameters:
sample, n=300
proportions of rooms reserved, p=6%
We first get the sample mean,
Sample mean=n*p
=300*6%
=18
Now, we get population mean according to binomial distribution, μ'
μ=n-sample mean
=300-18
=282
We get the standard deviation, σ
σ=(sample mean*(1-p))^1/2
=(18*(1-6%))^1/2
=4.11
We now, calculate z-score:
z=(x-μ)/σ, given x should be at least 275
z=(275-282)/4.11
=-1.703
Now, we have p(x>275)=p(z>-1.703)
From z-score of probabilities, we have p(z>-1.703) as 0.95572
So, p(x>275)=0.95572
=0.96
Hence, the probability that at least 275 rooms are occupied is 0.96
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