a stone dropped into a still pond sends out a circular ripple whose radius increases at a constant rate of 3.3 ft/s. how rapidly is the area enclosed by the ripple increasing at the end of 6.4 seconds?



Answer :

In 139.4 [tex]\pi[/tex] [tex]ft^2[/tex]sec rapidly is area of enclosed by the ripple increasing at the end of 6.4 seconds.

What is area of circle?

 For measuring the area occupied by a circular field or plot, use the area of a circle formula. The area formula will allow us to determine how much fabric is required to completely cover a circular table, for example. We can determine the boundary length, or the circle's circumference, using the area formula.

Here area of circle

=> A= π[tex]r^2[/tex]--------> 1

Differentiating 1 with respect to to time then

=> [tex]\frac{dA}{dt}= 2\pi r\frac{dr}{dt}[/tex]

If the radius is  increasing at a constant rate 3.3ft/sec then after 6.4 seconds, radius is

=> 6.4*3.3=21.12 ft.

We know [tex]\frac{dr}{dt}= \frac{3.3ft}{sec}[/tex] and so ,

=> [tex]\frac{dA}{dt}[/tex] = 2*[tex]\pi[/tex]*21.12*3.3=139.4 [tex]\pi[/tex] [tex]ft^2[/tex]sec.

Hence In 139.4 [tex]\pi[/tex] [tex]ft^2[/tex]sec rapidly is area of enclosed by the ripple increasing at the end of 6.4 seconds.

To learn more about area of circle refer the below link

https://brainly.com/question/10645610

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