if there were no air resistance, how long would it take a free-falling skydiver to fall from a plane at 3100 m to an altitude of 490 m , where she will pull her ripcord? what would her speed be at 490 m ? (in reality, the air resistance will restrict her speed to perhaps 150 km/h .)

Speed is the rate at which an object moves along a path in time, whereas velocity is the rate and direction of movement.
In other words, velocity is a vector, whereas speed is a scalar value.
For example, 50 km/hr (31 mph (ca. 50 km/h)) describes the speed of a car traveling along a road, whereas 50 km/hr west describes the velocity.

Calculation

a) initial height, [tex]h_{i}[/tex] = 3100 m

[tex]h_{f}[/tex] = 490 m

time taken, t

Using the second equation is motion

3100–490 = 0.5 × 9.8 ×[tex]t^{2}[/tex]

solving for t

t = 23.07 s

b) let the speed is u

u =[tex]\sqrt{2*g*(h_{i} -h_{f} )}[/tex]

u = [tex]\sqrt{(2*9.8 * (3100-490))}[/tex]

u = 226 m/s

Hence, her speed is 226 m/s

To learn more about speed, refer to

https://brainly.com/question/26046491

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tutorconsortium127 tutorconsortium127 · Answer 2 · 2022-11-14T23:47:56-05:00

Her speed be at 490 m will be 226 m/s.

Speed is the rate at which an object moves along a path in time, whereas velocity is the rate and direction of movement.
In other words, velocity is a vector, whereas speed is a scalar value.
For example, 50 km/hr (31 mph (ca. 50 km/h)) describes the speed of a car traveling along a road, whereas 50 km/hr west describes the velocity.

initial height,[tex]h_i[/tex] = 3100 m

[tex]h_f[/tex] = 490 m

time taken, t

Using the second equation is motion

3100–490 = 0.5 × 9.8 ×

solving for t

t = 23.07 s

b) let the speed is u

[tex]&\mathrm{u}=\sqrt{2 * g *\left(h_i-h_f\right)} \\[/tex]

[tex]&\mathrm{u}=\sqrt{(2 * 9.8 *(3100-490))}[/tex]

u = 226 m/s

Hence, her speed is 226 m/s

To learn more about speed, refer to

brainly.com/question/26046491

#SPJ4