Answer :
a) Sample mean of set is 36.375.
b) Standard deviation of sample is 6.66208.
Define mean and standard deviation.
The average degree of variability in your dataset is represented by the standard deviation. It reveals the average deviation of each statistic from the mean. In general, values with a large standard deviation are spread out from the mean, and those with a low standard deviation are grouped together near to the mean.
Given,
a) Mean
Total number of values = 16
= Sum/Total number of values
= 34 +45+ 27 +33 +38+ 41+ 45 +29 +30+ 39 +34 +40 +28 +33 +36+ 50/16
= 582/16
= 36.375
Sample mean of set is 36.375.
b) Sample standard deviation
S² = ∈ (x i - x)²/N-1
S² = 666.75/16-1
S² = 44.383333
S = √44.38333
S = 6.66208
Standard deviation of sample is 6.66208.
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