Answer :
Using the concepts of atwood machine, we got 4.05m[tex]s^{-2}[/tex]. is the acceleration of system when released from rest.
We know very well that in atwood`s two bodies having different mass are hanged around the pulley.
The accceleration of the atwood is given by :
a=((m2-m1)/(m2+m1))×g, where m2 is the mass of heavier body,m1 is the mass of lighter body and g is the acceleration due to gravity.
So, according to question m2=11.9,m1=4.93 and g=9.8
So, on putting the value in above formula, we got
a=[(11.9-4.93)/(11.9+4.93)]×9.8
=>a=[(6.97)/(16.83)]×9.8
=>a=4.05m[tex]s^{-2}[/tex].
Hence, an atwood machine in which two masses: one of mass 4.93 kg and the other of mass 11.9 kg. when released from rest, the acceleration of the system is 4.05m[tex]s^{-2}[/tex].
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