Answer :
The acceleration of the wheelbarrow is 0.621 m/s^2 .
There will be equal force applied on both side, in that case the object will be having zero motion and zero acceleration.
But in the case when there is more force applied in one direction than other side force then there will be acceleration on the object.
This acceleration is equal to the ΔF/m.
where ΔF is the difference of the forces applied on the both direction
and m is the total mass of the object.
According to the question, we have m = 37Kg
ΔF = (36-13) n = 23 n
so a = 23/37 = 0.621 m/s^2
so acceleration of the wheelbarrow is 0.621 m/s^2 .
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