Answer :
The test statistic's p-value is -2.785.
According to A publisher, 45% of its readers own a particular make of car.
Claim: An executive in marketing would like to test the claim that the percentage is different from what is reported.
[tex]H_{o}[/tex]: p = 0.45
[tex]H_{a}[/tex]: p ≠ 0.45
a random sample of 300 found that 37% of the readers owned a particular make of car.
= 37% × 300
= (37 ÷ 100) × 300
X = 111
n= 300
One sample proportion test should be used.
p-vector = x ÷ n,
p-vector = 111 ÷ 300
p-vector = 0.37
The test statistic's formula,
= [tex]\frac{p-q}{\sqrt{\frac{pq}{n} } }[/tex]
test statistic = [tex]\frac{0.37- 0.45}{\sqrt{\frac{0.45(1-0.45)}{300} } }[/tex]
≈ -2.7851
thus, the p-value of the test statistic is -2.7851.
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