Answer :
The speed of the faster car is 40 miles/hr.
both cars travel for same time , so let that time be 't'
car 1 :
distance travelled = 75 miles
let the speed of the car be = x miles/hr
∴ time (t) = distance / speed
t = 75 / x .............(1)
car 2 :
distance travelled = 100 miles
speed of the car is = x + 10 miles/hr ( already provided )
∴ time ( t) = distance / speed
t = 100/ (x+10) ..............(2)
now as the time for both the cases is same , so we equate eqn (1) and eqn (2) .
∴ 75/x = 100/ (x+10)
3x + 30 = 4x
x = 30
so the speed of the 1st car will be 30 miles / hr
and the speed of the 2nd car ( faster car ) will be x + 10 = 40 miles/hr
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