a hockey puck of mass 150.0 g is sliding due east on a frictionless table with a speed of 10.0 m/s. suddenly, a constant force of magnitude 5.0 n and direction due north is applied to the puck for 1.5 s. find the momentum at the end of the 1.5s in component form.



Answer :

The momentum at the end of the 1.5s in component form a speed of 1.23 m/sec.

mgh=1/2mv²

v=√2gh

v=3.7 m/s

elastic collision

V=(m₁-m₂/m₁+m₂)v

=0.5-2.5/.5+2.5(3.7)

V₁=-2.47 m/sec

V₂=(2m₁/m₁+m₂)V

=2(0.5)/0.5+2.5

V₂=1.23 m/sec

In Newtonian mechanics, momentum is calculated as the sum of an object's mass and velocity. It has both a magnitude and a direction, making it a vector quantity. The momentum of an object is determined by its mass (m) and its velocity (v). Since velocity is a vector and mass is a scalar, momentum is a vector quantity. Momentum can be viewed as a body's "power" while it is moving, or the amount of force it can exert on another body. For instance, a baseball (small mass) thrown quickly can have the same momentum as a bowling ball (big mass) going extremely slowly (low velocity) (high velocity).

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