calculate the %cw for a sample of 1040 steel that has an original diameter of 12 mm and a final diameter of 10 mm.



Answer :

The new yield strength of the 1040 steel will be the intercept on the curve for 30.56 %of cold work which is between700 to 800 MPA

Given original diameter do = 12 mm

Ao = [tex]\pi[/tex]/4 x 12² = 113.097 mm²

Deformed diameter d =10mm

Ad = [tex]\pi[/tex]/4 x 10² = 78.54 mm²

Degree of cold work %CW = (Ao - Ad/Ao)X 100

                                             =(113. 097 - 78. 54/113.097) x 100

                                             = 30.56%

% CW is 30.56 %

Therefore, the intercept on the curve for 30.56% of cold work, which is between 700 and 800 MPA, will represent the new yield strength of the 1040 steel.

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