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the per capita consumption of meat by people in the united states in a recent year was normally distributed with a mean of 218.4 pounds and standard deviation of 42 pounds. a random selection of 30 people was taken. what is the probability that the sample mean is less than 200 pounds? (notice i used the words sample mean!)



Answer :

The probability that the sample mean is less than 200 pounds is 33% or 0.33

Given that,

The average annual meat consumption in the United States was 218.4 pounds, with a standard deviation of 42 pounds, and was normally distributed. A random sample of 30 individuals was chosen.

Mean  (μ) = 218.4

Standard deviation (σ) =42        

Probability = P(X< 200) = P[(X-μ ) / σ < (200-218.4) /42 ]

= P(z <-0.44 )

Using z table                                            

=0.3300

Probability=0.3300                                                        

Therefore, 33% or 0.33 of the time, the sample mean will weigh less than 200 pounds.

Learn more about Standard deviation :

brainly.com/question/14747159

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