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n a recent survey in a statistics class, it was determined that only 60% of the students attend class on fridays. from past data it was noted that 98% of those who went to class on fridays pass the course, while only 20% of those who did not go to class on fridays passed the course. a. what percentage of students is expected to pass the course?



Answer :

The percentage of students expected to pass the course is 66.8%

The given data represents;

In a recent survey in a statistics class, it was determined that only 60% of the students attend class on Fridays. from past data, it was noted that 98% of those who went to class on Fridays passed the course, while only 20% of those who did not go to class on Fridays passed the course.

We need to find the percentage of students who are expected to pass the course.

Let 'A' be the event of passing,

     'B' be the event of attending on Fridays.

P (A I B) = 0.98 * P (A I B') = 0.2

P (B) = 0.6

Then, P (B') = 1 - 0.6

                  = 0.4

→ P (A ∩ B) = P (A I B) * P (B)

                 = 0.98 * 0.6

                 = 0.588

→ P (A ∩ B') = P (A I B') * P (B)

                  = 0.2 * 0.4

                  = 0.08

∴ P(A) = P (A ∩ B) + P (A ∩ B')

          = 0.588 + 0.08

          = 0.668

Hence, the percentage of students expected to pass the course is 66.8%

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