an object undergoing simple harmonic motion takes 0.12 s to travel from one point of zero velocity to the next such point. the distance traveled between those points by the object is 41.6 cm. calculate the period.



Answer :

The period of the  object undergoing simple harmonic motion   is

simple harmonic motion sometime shortened as SHM may be a sort of periodic movement where the restoring drive on the moving object is straightforwardly relative to the magnitude of the displacement of the object and acts towards the object's equilibrium position. It comes about in an oscillation that proceeds inconclusively, on the off chance that uninhibited by friction or any other dissemination of energy.

we are given the time taken to complete the distance covered between two  zero velocity  points apart from the distance of   41.6 cm which is  0.12 so the period  will be  = 2T = 2 * 0.12 = 0.24 s

to know more about  simple harmonic motion refer to the  link https://brainly.com/question/28940722?referrer=searchResults.

#SPJ4

Other Questions