a square with side length 2 and a circle share the same center. the total area of the regions that are inside the circle and outside the square is equal to the total area of the regions that are outside the circle and inside the square. what is the radius of the circle?



Answer :

The radius of the circle which is overlapping the square is 1.12.

The length of side of the square is 2. Let us say that the radius of the circle is R.

The circle and the square are overlapping on each other.

The area of the region that are outside the circle but inside the square are equal to the area of the region which are inside the circle but outside the square.

Let us name the area of the region that are outside the circle but inside the square as M.

Let us name the area of the region which are inside the circle but outside the square as N.

Let us say that the area that is common in both is C.

The area of the square is 4.

So, according to the question,

M + C = 4

And,

N + C = πR²

And we know, M = N,

So,

C - πR² = C - 4

R = 2/√π

R = 1.12.

So, the radius of the circle is 1.12

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