a 280 g bird flying along at 6.0 m/s sees a 11 g insect heading straight toward it with a speed of 30 m/s. the bird opens its mouth wide and enjoys a nice lunch. what is the bird's speed immediately after swallowing?



Answer :

The bird's speed immediately after swallowing is 6.91 m/s

The conservation of momentum states that, within a few problem domains, the quantity of momentum remains regular; momentum is neither created nor destroyed, but best modified through the movement of forces as described by means of Newton's laws of motion.

Calculation:-

Mass of bird m₁ = 280 g = 0.28 kg

velocity v₁ = 6 m/s

mass of insect m₂ = 11g = 0.011 kg

velocity = 30 m/s

applying conservation of momentum considering bird and insect as a close system

m₁v₁ + m₂v₂ =  m₁v₁ + m₂v₂ V

V =  m₁v₁ + m₂v₂ /m₁ + m₂

  = (0.28 × 6 + 0.011 × 30) /  0.28 +0.011

  = (1.68 + 0.33) / 0.291

   = 2.01 / 0.291

   = 6.91 m/s

The regulation of conservation of momentum states that in an isolated machine the full momentum of or more bodies appearing upon each other stays regular except an outside force is applied. therefore, momentum can neither be created nor destroyed.

A 'closed device' is something that isn't laid low with outside forces. that is known as the principle of conservation of momentum. Momentum is conserved in collisions and explosions.

Learn more about the conservation of momentum here:-https://brainly.com/question/22257327

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