Answer :

The answer is  2.416 m/s^2.

Solution:

friction force on the upper block = umg

= 0.13*2*9.81

= 2.5506 N

so writing the equation of motion for the upper block

T - f = ma

or T-2.5506 = 2a

writing the equation of motion for the lower block

mg-T=ma

or 9.8-T=a

Hence, we get a  = 2.416 m/s^2.

Since the top block slides to the right, the frictional force acting on it acts to the left. His reaction wall acts on the forward-acting lower block. The frictional force absorbs x mechanical energy from the upper block, but transfers only y mechanical energy to the lower block. To find the acceleration of the body in terms of angle and coefficient of friction.

A material modulus value of 1 means that the friction force is equal to the normal force. This means that the force required to move an object is equal to its weight. An object may have a friction value greater than 1. There are two types of friction coefficients: static friction coefficient and dynamic friction coefficient. The former is sometimes called the initial friction coefficient and the latter is sometimes called the dynamic or sliding friction coefficient.

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