The probability that the sample mean selling price was more than $210,000 is 0.9772.
The given values are:
The mean selling price(μ) = $215000
Standard deviation(σ) = $25000
The random sample (n) = 100
We have to find the probability that the sample mean selling price was more than $210000.
z-score with z-bar= 210000
z = (x-bar - μ) / (σ/ √n)
= ( 210000 - 215000) / (25000/ √100)
= -5000/ 2500
=-2
Using z-tables, the probability is:
Probability = P[z> -2]
= 1 - 0.0228
= 0.9772
Therefore the probability is 0.9772.
To know more about the probability refer to the link given below:
https://brainly.com/question/13604758
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