The rate of change of radius of the circle when the radius of the circle is 44 feet is 0.64 ft/s.
The area of the circle with radius R us given by,
A = πR²
It is given that the area is increasing at a constant rate of 178 square feet per second.
dA/dt = 178 ft²/s
Also, A = πR²
Differentiating A with respect to time,
dA/dt = 2πR.dR/dt
The rate of change of the radius is asked when the radius is 44 feet.
So, putting R = 44 ft.
dA/dt = 2π(44)dR/dt
178 = 2π(44)dR/dt
dR/dt = 0.64 ft/s
So, the rate of change of radius is 0.64 ft/s.
To know more about rate of change, visit,
https://brainly.com/question/25184007
#SPJ4