Answer :
The probability that no one enters between 12:00 and 12:05 is 0.082.
The probability that at least 4 people enter the casino during that time is 0.242
Given that people enter the casino at the rate of 1 every 2 minutes. A random variable X is defined as the number of people entering the casino between the time period of 12:00 and 12:05. Since we are given in the question that people enter the casino at the rate of 1 every minute, hence in the given time period they enter at the rate of 2.5.
P(X=0) = [tex]e^{-2.5}[/tex] = 0.082
Hence the probability that no one enters between 12:00 and 12:05 is 0.082.
The required probability is simply
P(X≥4) = 1 - P(X=0) - P(X=1) - P(X=2) - P(X=3)
= 1 - [tex]e^{-2.5}[/tex] - 2.5[tex]e^{-2.5}[/tex] - (((2.5)² / 2)[tex]e^{-2.5}[/tex] ) - (((2.5³)/3!)[tex]e^{-2.5}[/tex])
= 0.242
Hence, the probability that at least 4 people enter the casino during that time is 0.242
To learn more about time and probability,
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