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assume that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches. the u.s. marine corps requires that the heights of men be between 64 and 78 inches. if 500 men want to enlist in the u.s. marine corps, how many would you not expect to meet the height requirements?



Answer :

varshamittal029

The percentage of men who didn't expect to meet the height requirements be 96.29%

Given, that the heights of men are normally distributed with a mean of 69.0 inches and a standard deviation of 2.8 inches.

Find the percentage of men who meet the height requirements.

z(64) = (64-69)/2.8 = 1.7857

z(78) = (78-69)/2.8 = 3.2143

P(64 <= x <= 78) = P(1.78457<= z <=3.2143) = 0.0371 = 3.71%

So, the percentage of men who meet the height requirements be 3.71%

Now, the percentage men who didn't expect to meet the height requirements be

100 - 3.71 = 96.29%

Hence, the percentage of men who didn't expect to meet the height requirements be

96.29%

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