Answer :
The average force of kinetic friction between the block and the surface is 0.00601N
v=u +at
v=at
t=v/a -----------1
d=at²/2 ------------2
Putting the value of t in eq 2
d=v²/(2a)
a=v²/(2d) -----------3
Putting the value of a in equation F=ma
F=ma ⇒ m [v²/(2d)]
In the question , m= 5g = 0.005kg , ∨=325m/s
Meanwhile distance=speed x time
distance=[ 325 x 135 ]
distance , d = 43875 m
F= m [v²/(2d)]
=0.005 {(325)²/(2x43875)}
=528.125/87750
=0.00601851852 N
≅0.00601N is the approximate force of kinetic friction between the block and surface.
To learn more about kinetic friction -
https://brainly.com/question/13754413
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