80°,20° or 50°,50° are possible for the other two angles.
Given:
One angle of an isosceles triangle measures 80°.
we assumed that the 80° is one of the equal angles, then there is another 80° angle.That makes 160°.
Since a triangle always totals 180°,
180° - 160° = 20°.
if the 80° was the only different angle instead,the two remaining angles total:
180 - 80 = 100
Since we have two identical angles remaining, we need only divide the 100° in half to get the final answer:
100/2 = 50°.
Therefore 80°,20° or 50°,50° are possible for the other two angles.
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