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these stick figures are each in a hurry to catch a flight. they are both walking at a speed of 1 m/s on a walkway that has a velocity of 0.5 m/s to the west. explain which stick figure is moving more quickly relative to the ground.



Answer :

The stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.

Vsg = Vsw + Vwg

Vsg = Relative velocity of stick figure wrt ground

Vsw = Relative velocity of stick figure wrt walkway

Vwg = Relative velocity of walkway wrt ground

Let the stick figure that is walking to the west be A and the stick figure that is walking to the east be B.

For A,

Vsw = - 1 m / s

Vwg = - 0.5 m / s

Vsg = - 1 - 0.5

Vsg = - 1.5 m / s

For B,

Vsw = 1 m / s

Vwg = - 0.5 m / s

Vsg = 1 - 0.5

Vsg = 0.5 m / s

The negative symbol indicates direction. So Vsg for A > Vsg for B

Therefore, the stick figure that is walking at a velocity of 1 m / s to the west is moving quickly relative to the ground than the stick figure that is walking at a velocity of 1 m / s to the east.

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