a sum of money was shareed between aziz and ahmad in the ratio of 4:7. aziz reeceived 21 dollars less than ahmad. find the total sum of money shareed by both of them



Answer :

The total sum of money is 77 dollars .

Let the total sum of money be x .

⇒ Aziz's share = 4x / 11

   Ahmad's share = 7x / 11

Given : Aziz received 21 dollars less than Ahmad

⇒ 4x / 11 = ( 7x / 11 ) - 21

Solving the above linear equation in one variable ,

( 7x - 4x ) / 11 = 21                      ( taking like terms together )

3x = 21 * 11

x = 7 * 11

x = 77

Aziz's share = ( 4 / 11 ) * 77 = 28

Ahmad's share = ( 7 / 11 ) * 77 = 49

Total Sum of money = 28 + 49 = 77 dollars .

Hence , the total sum of money = 77 dollars .

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https://brainly.com/question/28908117

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