2.10-kg block of wood is attached to a spring with a spring constant of 150 n/m. the block is free to slide on a horizontal frictionless surface once the spring is stretched and released. a 1.00-kg block of wood rests on top of the first block. the coefficient of static friction between the two blocks of wood is 0.450. what is the maximum speed that this



Answer :

Knowing the kinetic static force coefficient.

What is oscillation ?

Oscillation is the process by which a quantity or measure varies in time around its equilibrium value. Another definition of oscillation is the periodic variation of a substance between two values or around its central value.

What is kinetic force?

A force that acts between moving surfaces is referred to as "kinetic friction." A force acting in opposition to the direction of a moving body on the surface is felt. The two materials' coefficients of kinetic friction will determine how much force is applied.

For both blocks to oscillate together w^2=K/((M+M))

Maximum accelartion =a_(n= w^2 ) A= K/((M+M))A

For ⏊ kg block, μmg = 〖ma〗(n= )  μg

μg =K/((M+M))A

= 0.45×9.8 = 150/((2.1+1)) A

A=0.0914m

Max speed, vm=wA=  √(k/(M+M)) A

=√(150/((2.1+1))) × 0.0914

= v(m=) 0.636 m/s

Therefore, the maximum speed is  0.636 m/s.

Learn more about oscillation from the given link.

https://brainly.com/question/12622728

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