a block of mass m starts from rest and slides down a frictionless semi-circular track from a height h as shown below. when it reaches the lowest point of the track, it inelastically collides with a stationary piece of putty also having mass 2m . the block and the putty stick together and continue to slide. what is the maximum height that the block-putty system could reach?



Answer :

The maximum height of that block-putty system is h/4.

Whtat is inelastic collision?

A collision in which a portion of the kinetic energy of the colliding particles is converted into another type of energy.

What is velocity?

The primary determinant of an object's position and rate of motion is its velocity. It can be explained as the distance an object travels in one unit of time. The object's displacement in a given amount of time is called velocity.

The velocity of block just before hitting the putty (by energy conservation)

K.Ei+P.Ei=K.Ef+P.Ef

⇒0+mgh=21mv2

⇒v=[tex]\sqrt{2}[/tex]gh

Let the common velocity of both block and putty be v'

At collision momentum balance:

mv=mv′+mv′

⇒[tex]\sqrt{2}[/tex]gh=2v′

⇒v′=[tex]\sqrt{g/h}[/tex]

Again applying energy conservation (both block and putty at max height)

K.Ei+P.Ei=K.Ef+P.Ef

⇒1/2 2mv²=2mgh′

⇒1/2 gh/2=gh′

⇒h′=h/4

Therefore, the maximum height is h/4.

learn more about inelastic collides from the given link.

https://brainly.com/question/7694106

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