Answer :
Ana and Bonita were born nn year apart and its value of nn is 12.
Here we have to find nn which difference in the year in which Ana and Bonita were born.
Let x be the age of Ana and y be the age of Bonita.
It is given that last year Ana was 5 times as old as Bonita so from this statement we get the first equation:
x - 1 = 5(y -1)
x -1 = 5y - 5
5y -x = 4--------(1)
The second statement is Ana is square of Bonita's age. From this we get another equation:
x = y²-----------(2)
Putting equation 2 in equation 1 we get:
5y - y² = 4
y² - 5y +4 = 0
y² - 4y - y + 4 = 0
y(y-4) -1(y -4) = 0
(y - 4)(y -1) = 0
y = 4,1
As x = y²
x = 4² = 16 or x = 1² =1
We cannot take 1 as there is a difference in their age
So we get x = 16 and y =4
So the difference in their age = 16-4= 12
Therefore we get the value of nn as 12.
To know more about the age refer to the link given below:
https://brainly.com/question/1581212
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