Answer :
The percent by mass of salt in the mixture is 48.35%.
Solution:
Total mixture (Sand + salt) = 2.95g
Recovered salt = 1.33g
salt percentage = [tex]\frac{Salt weight}{Total weight of mixture} *100%[/tex]
Salt % = [tex]\frac{1.33}{2.95} *1005[/tex]
= 48.35%
salt in the mixture = 48.35%.
To determine the percentage of salt in a mixture, simply divide the mass of salt by the total mass of the mixture and multiply by 100%. A percentage is essentially a ratio plotted on a 100-point scale. Divide the mass of water lost by the mass of hydrate and multiply by 100. Multiply the molar mass of the hydrate by 100 by the mass of water in the moles of the hydrate.
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